0=16x^2-1/9

Solution for 0=16x^2-1/9 equation:

0=16x^2-1/9

We move all terms to the left:

0-(16x^2-1/9)=0

We add all the numbers together, and all the variables

-(16x^2-1/9)=0

We get rid of parentheses

-16x^2+1/9=0

We multiply all the terms by the denominator


-16x^2*9+1=0

Wy multiply elements

-144x^2+1=0

a = -144; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-144)·1
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-144}=\frac{-24}{-288}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-144}=\frac{24}{-288}
=-1/12
$